What is the slope- intercept form of a line that goes through the points (2,4) and (-3,-11)

YES 

$$slope=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}=\frac{-11-4}{-3-2}=\frac{-15}{-5}=3$$

Oh I read the question wrong.

Never mind I will keep going from here.

$$y=mx+b\\
y=3x+b\\
\mbox{sub in a point that you have (2,4) will do nicely}\\
4=3*2+b\\
4=6+b\\
-2=b\\
\mbox{Therefore the equation is}\\
y=3x-2$$

Slope intercept form is: y=$${\frac{{\mathtt{rise}}}{{\mathtt{run}}}}$$ x+(y-intercept)

y=3x+(-2)