What is the slope of h(x) = –3(x^2) + 1 when x = –2?

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Guest Dec 10, 2014

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Best Answer

If h(x) = -3x² + 1,

then h'(x) = -6x

Thus, h'(-2) = -6(-2) = 12 <-- slope when x = -2.

geno3141 Dec 11, 2014

geno3141 · Answer 1 · 2014-12-11T03:21:34

If h(x) = -3x² + 1,

then h'(x) = -6x

Thus, h'(-2) = -6(-2) = 12 <-- slope when x = -2.