We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
97
2
avatar

What is the slope of the tangent line to g(x)=cos(x+pi) at x=pi

 Nov 27, 2018

Best Answer 

 #2
avatar+18337 
+2

This was answerd just a day or two ago:

 

remember    cos(x+pi) = -cos(x)

 

d/dx (-cos(x)) = sinx      and at pi    sin(x) = 0

 Nov 27, 2018
 #1
avatar+5172 
+1

The slope of the line tangent to a curve at a point is just the derivative of that curve evaluated at the point.

 

\(g(x) = \cos(x+\pi)\\ \dfrac{dg}{dx}(x) = -\sin(x+\pi)\\ \dfrac{dg}{dx}(\pi) = -\sin(\pi + \pi) = \\ \sin(2\pi) = 0\\ \text{hence the slope of the line tangent to }g(x) \text{ at }x=\pi \text{ equals }0.\)

.
 Nov 27, 2018
 #2
avatar+18337 
+2
Best Answer

This was answerd just a day or two ago:

 

remember    cos(x+pi) = -cos(x)

 

d/dx (-cos(x)) = sinx      and at pi    sin(x) = 0

ElectricPavlov Nov 27, 2018

17 Online Users

avatar
avatar
avatar