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What is the smallest value of \(x\) that satisfies the equation \(8x^2 - 38x + 35 = 0\)? Express your answer as a decimal.

 Jul 12, 2022
edited by Guest  Jul 12, 2022

Best Answer 

 #2
avatar+124676 
+1

Factor  as

 

(4x - 5) (2x - 7)  =  0

 

The smaller   value of x that solves this is

 

4x - 5   = 0

 

4x  = 5

 

x = 5/4  =  1.25

 

 

cool cool cool

 Jul 13, 2022
 #1
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0

By the quadratic formula, the roots are 5/2 = 2.5 and 7/4 = 1.75.  So the answer is 1.75.

 Jul 12, 2022
 #2
avatar+124676 
+1
Best Answer

Factor  as

 

(4x - 5) (2x - 7)  =  0

 

The smaller   value of x that solves this is

 

4x - 5   = 0

 

4x  = 5

 

x = 5/4  =  1.25

 

 

cool cool cool

CPhill Jul 13, 2022

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