+33653 2x^2- 6x+2=0 Divide all terms by 2:
x^2 - 3x + 1 = 0 Use the quadratic equation:
x1 = (3 + sqrt(3^2 - 4))/2 → 3/2 + sqrt(5)/2
x2 = (3 - sqrt(3^2 - 4))/2 → 3/2 - sqrt(5)/2
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+14985 Hello dayor!
what is the solution for 2x^2- 6x+2=0
\(2x^2-6x+2=0\)
\(a=2; \ b=-6; \ c = 2\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(\)\(x = {6 \pm \sqrt{36-4 \times 2 \times 2} \over 2 \times 2}\)
\(x= \frac{6 \pm \sqrt{20} }{4} \)
\(x= \frac {6 \pm 4.472135955}{4}\)
\(x_{1}=2.61803398875\)
\(x_{2}=0.38196601125\)
Greeting asinus :- ) 
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