what is the solution for x2+x-12=0

Factor it: x² + x - 12 = 0

This equation is in the ax² + bx + c form, so c is -12

Since c is negative, you know that the factoring would have one positive x-value and one negative x-value; a positive number times a negative number would be negative.

So now you know that it will be:

(x + __ ) * (x - __ ) = 0

Now find the factors of -12 that will add/subtract to get positive 1 (since your b-value is 1x.) -3 and 4 multiply to get -12, and add to get 1

Therefore, it would be:

(x + 4) * (x - 3) = 0

So x would be the number that makes the value in the parentheses equal to 0.

-4 + 4 = 0 and 3 - 3 = 0

So x = - 4, 3