#1**+1 **

√ [ 2x - 3 ] + 3 = x subtract 3 from both sides

√ [ 2x - 3 ] = x - 3 square both sides

2x - 3 = x^2 - 6x + 9 subtract/add 2x, 3 to both sides

0 = x^2 - 8x + 12 factor

(x - 6) ( x - 2) = 0

Setting each factor to 0 and solving for x gives x = 6 and x = 2

Only the first solution solves the original problem

CPhill
Mar 2, 2018