What is the solution to 3x^2 + 4x - 8 = 0?
A) x = -4 ± 4√7
B) x = -4 ± 7√4/6
C) x = -2 ± 2√7/3
D) x = 2 ± 2√7/3
E) x = 2 ± 2√7
3x^2 + 4x - 8 = 0
Use the quad formula with a = 3 b = 4 and c = -8
So we have that
-4 ±√ [ 4^2 - (4 * 3 * -8) ] -4 ±√[16 + 96] -4 ± 4√ [ 1 + 6]
x = _____________________ = _____________ = ____________ =
2 * 3 6 6
- 2 ± 2√7
________ = "C"
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