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What is the solution to the equation 7(x3+3x1)=17x+7(x3+11)?

 Dec 4, 2014

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7(x3+3x1)=17x+7(x3+11)7x3+21x7=17x+7x3+777x3+4x7=7x3+777x3+4x=7x3+844x=84x=21

 Dec 4, 2014
 #1
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Best Answer

7(x3+3x1)=17x+7(x3+11)7x3+21x7=17x+7x3+777x3+4x7=7x3+777x3+4x=7x3+844x=84x=21

shaniab29544 Dec 4, 2014

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