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what is the solution to the following equation v 2 =25/81

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what is the solution to the following equation v2=25/81

Aug 25, 2017

#1
+2339
+1

I'm assuming that we are solving for v in the equation $$v^2=\frac{25}{81}$$. Let's do that!

 $$v^2=\frac{25}{81}$$ Take the square root of both sides to isolate v. Of course, the square root always results in 2 answers: The positive and negative. $$v=\pm\sqrt{\frac{25}{81}}$$ "Distribute" the square to both the numerator and denominator. $$v=\pm\frac{\sqrt{25}}{\sqrt{81}}$$ Now, simplify both the numerator and denominator. $$v=\pm\frac{5}{9}=\pm0.\overline{55}$$
Aug 25, 2017

#1
+2339
+1

I'm assuming that we are solving for v in the equation $$v^2=\frac{25}{81}$$. Let's do that!

 $$v^2=\frac{25}{81}$$ Take the square root of both sides to isolate v. Of course, the square root always results in 2 answers: The positive and negative. $$v=\pm\sqrt{\frac{25}{81}}$$ "Distribute" the square to both the numerator and denominator. $$v=\pm\frac{\sqrt{25}}{\sqrt{81}}$$ Now, simplify both the numerator and denominator. $$v=\pm\frac{5}{9}=\pm0.\overline{55}$$
TheXSquaredFactor Aug 25, 2017