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# what is the solution to the following equation v 2 =25/81

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## what is the solution to the following equation v2=25/81

Guest Aug 25, 2017

#1
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I'm assuming that we are solving for v in the equation $$v^2=\frac{25}{81}$$. Let's do that!

 $$v^2=\frac{25}{81}$$ Take the square root of both sides to isolate v. Of course, the square root always results in 2 answers: The positive and negative. $$v=\pm\sqrt{\frac{25}{81}}$$ "Distribute" the square to both the numerator and denominator. $$v=\pm\frac{\sqrt{25}}{\sqrt{81}}$$ Now, simplify both the numerator and denominator. $$v=\pm\frac{5}{9}=\pm0.\overline{55}$$
TheXSquaredFactor  Aug 25, 2017
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#1
+1829
+1
I'm assuming that we are solving for v in the equation $$v^2=\frac{25}{81}$$. Let's do that!
 $$v^2=\frac{25}{81}$$ Take the square root of both sides to isolate v. Of course, the square root always results in 2 answers: The positive and negative. $$v=\pm\sqrt{\frac{25}{81}}$$ "Distribute" the square to both the numerator and denominator. $$v=\pm\frac{\sqrt{25}}{\sqrt{81}}$$ Now, simplify both the numerator and denominator. $$v=\pm\frac{5}{9}=\pm0.\overline{55}$$