+2440 I'm assuming that we are solving for v in the equation \(v^2=\frac{25}{81}\). Let's do that!
| \(v^2=\frac{25}{81}\) | Take the square root of both sides to isolate v. Of course, the square root always results in 2 answers: The positive and negative. |
| \(v=\pm\sqrt{\frac{25}{81}}\) | "Distribute" the square to both the numerator and denominator. |
| \(v=\pm\frac{\sqrt{25}}{\sqrt{81}}\) | Now, simplify both the numerator and denominator. |
| \(v=\pm\frac{5}{9}=\pm0.\overline{55}\) | |
+2440 I'm assuming that we are solving for v in the equation \(v^2=\frac{25}{81}\). Let's do that!
| \(v^2=\frac{25}{81}\) | Take the square root of both sides to isolate v. Of course, the square root always results in 2 answers: The positive and negative. |
| \(v=\pm\sqrt{\frac{25}{81}}\) | "Distribute" the square to both the numerator and denominator. |
| \(v=\pm\frac{\sqrt{25}}{\sqrt{81}}\) | Now, simplify both the numerator and denominator. |
| \(v=\pm\frac{5}{9}=\pm0.\overline{55}\) | |
