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what is the solution to the following equation v2=25/81

Guest Aug 25, 2017

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 #1
avatar+1366 
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I'm assuming that we are solving for v in the equation \(v^2=\frac{25}{81}\). Let's do that!

 

\(v^2=\frac{25}{81}\) Take the square root of both sides to isolate v. Of course, the square root always results in 2 answers: The positive and negative.
\(v=\pm\sqrt{\frac{25}{81}}\) "Distribute" the square to both the numerator and denominator.
\(v=\pm\frac{\sqrt{25}}{\sqrt{81}}\) Now, simplify both the numerator and denominator.
\(v=\pm\frac{5}{9}=\pm0.\overline{55}\)  

 
 
TheXSquaredFactor  Aug 25, 2017
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1+0 Answers

 #1
avatar+1366 
+1
Best Answer

I'm assuming that we are solving for v in the equation \(v^2=\frac{25}{81}\). Let's do that!

 

\(v^2=\frac{25}{81}\) Take the square root of both sides to isolate v. Of course, the square root always results in 2 answers: The positive and negative.
\(v=\pm\sqrt{\frac{25}{81}}\) "Distribute" the square to both the numerator and denominator.
\(v=\pm\frac{\sqrt{25}}{\sqrt{81}}\) Now, simplify both the numerator and denominator.
\(v=\pm\frac{5}{9}=\pm0.\overline{55}\)  

 
 
TheXSquaredFactor  Aug 25, 2017

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