What Is The Square Root Of 1?

$${{\mathtt{1}}}^{{\mathtt{2}}} = {\mathtt{1}}$$

$${\sqrt{{\mathtt{1}}}} = {\mathtt{1}}$$

The square root of 1 is one

It is good to see you making good use of the web2 calc MG  :)

Thanks :)

I wouldn't have leanrt square and sqare root without your help.

I have something for you to think about  MG

$$\\(-1)^2=1\\ $so would it be correct to say that$\\ \sqrt{1}=-1\;\;\;?\\ also\\ what \;is\;\; -1^2\;\;\;?$$

I hate these mind boggling questions with negatives but i will see.

-1^2 would = -1 

Its the same as one just negative

but 1 itself is a positve and sqrt(1) =1

But why is  

  $$\\-1^2=-1 \;\;when\;\; -1*-1=+1\qquad $maybe you didn't know that?$$ $

They are the same question...?

But when put differently they give different answers...

I'm puzzled.

Lol

Lol i asked my brother he said it's +1. He said just to put it as -1*-1

 Negative number are hard the square / cube as they change from negative to positive 

like -2^3 = -8

But i dont know why the calc would analyse it like that and answer it as -1

ok I am just trying to trick you and to make you think

now i will tell you properly.

$$(+3)^2=3*3=+9$$

$$(-3)^2=-3*-3=+9$$

$$-3^2 = -3*3=-9$$       you can think of it like   $$-3^2=-1*3^2 = -1*9 = -9$$

$$\sqrt{9}=+3$$

$$\\\sqrt{9}\ne -3\\\\ $By convention the square root answer has to be positive$$ $.

Here is another question for you MG    

Hint: be careful, it is a bit tricky :)

$$5\frac{1}{4}-2\frac{5}{6}$$

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