what is the square root of 250 minus the square root of 40 divided by the square root of 2

$$\\\sqrt{250}-\frac{\sqrt{40}}{\sqrt2}\\\\
=\sqrt{250}-\frac{\sqrt{40}\sqrt2}{2}\\\\
=\sqrt{25}\sqrt{10}-\frac{\sqrt{10}\sqrt4\sqrt2}{2}\\\\
=5\sqrt{10}-\frac{\sqrt{10}*2*\sqrt2}{2}\\\\
=5\sqrt{10}-\sqrt{5}\sqrt2\sqrt2\\\\
=5\sqrt{10}-2\sqrt{5}\\\\$$

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