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0
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0 + 5 + (5 / 1.04) + (T3 /1.04) + (T4 /1.04) + (T5 / 1.04) + ..... + (T149 / 1.04) = ?

 

 

 

T1 + T2 + T3 + T4 + T5 + T6 + .... + T150 = ?

Guest Jun 2, 2018
 #1
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This is the sum of your 150 terms: 1/1.04 + 2/1.04 + 3/1.04..............150/1.04=

∑[N/1.04, N, 1, 150] =10,889.42.

 

I have a hunch that you are trying to solve a financial problem? If so, there is probably a formula for it which I would give to you if I knew what you were trying to solve!.

Guest Jun 2, 2018

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