What is the sum of the first six terms of the series?
40−10+2.5−0.625+...
We have a geometric series where the common ratio, r , = -1/4
The sum of the first six terms is given by
first term * [ 1 - r^6 ] / [ 1 - r ] =
40 [ 1 - (-1/4)^6 ] / [ 1 - - 1/4] =
40 [ 1 - ( 1/4096)] / [ 5/4] =
(4 * 40) [ 4096 - 1] / [ 5 * 4096 ] =
160 * 4095 / [ 20480 ] =
655200 / 20840 =
4095 / 128