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What is the sum of the first six terms of the series?

\( 48−12+3−0.75+\)

 Feb 20, 2020
 #1
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This is a geometric series  with   r =  (-1/4)

 

The sum  is  given by

 

48  [ 1  -  (-1/4)^6  ] / [ 1 - (-1/4) ]  =

 

48 [ 1  - (-1/4)^6]  / [ 5/4]  =

 

48 (4/5) [ 1  - (-1/4)^6 ]  =  

 

2457 / 64  = 

 

38.390625

 

 

cool cool cool

 Feb 20, 2020

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