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what is the sum of the multiples of 2 or 5 under 942?

Guest Oct 28, 2017
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If we consider 942 as the last term, then the number of terms of multiples of 2 would be:

942 / 2=471 terms - which counts 2 as the first term and 942 as the last term:

[F + L] / 2 x N =, where F=First term, L=Last term, N=Number of terms

[2 + 942] / 2 x 471=222,312

 

If we consider 940 as the last term, then the number of terms of multiples of 5 would be:

940 / 5 =188 terms.

[5 + 940] / 2 x 188 =88,830

Guest Oct 28, 2017

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