+0

# What is the total area of this composite figure rounded to the nearest inch?

0
1122
2

What is the total area of this composite figure rounded to the nearest inch? May 3, 2016

#1
+5

So basically what we have here is a rectangle on the bottom part, and then a half circle on the upper part. We'll need to add these two areas together to get the total area.

For the area of the rectangle, simply multiply 6 in times 2 in (base times height), giving you $$12\; in^2$$.

For the half circle, we know that the area of a circle is pi times the radius^2. Well, we don't know the radius but we do know the diameter of this circle, which is 6 in. The radius is always half the diameter, so the radius is 3 in.

Meaning, the area of this half circle is 1/2(pi((3 in)^2)) =

$$\frac{9}{2}\pi\; in^2$$

or aproximately

$$14.13\; in^2$$

Adding these together we get aproximately

$$28.13\; in^2$$

Which, if we're rounding to the nearest inch, would come out to

$$28\; in^2$$

Thanks for the question dude. If you have any additional questions or don't understand how I did this, or even see a mistake of mine, feel free to let us know and me or another forum member would love to help!

May 3, 2016
edited by NinjaDevo  May 3, 2016

#1
+5

So basically what we have here is a rectangle on the bottom part, and then a half circle on the upper part. We'll need to add these two areas together to get the total area.

For the area of the rectangle, simply multiply 6 in times 2 in (base times height), giving you $$12\; in^2$$.

For the half circle, we know that the area of a circle is pi times the radius^2. Well, we don't know the radius but we do know the diameter of this circle, which is 6 in. The radius is always half the diameter, so the radius is 3 in.

Meaning, the area of this half circle is 1/2(pi((3 in)^2)) =

$$\frac{9}{2}\pi\; in^2$$

or aproximately

$$14.13\; in^2$$

Adding these together we get aproximately

$$28.13\; in^2$$

Which, if we're rounding to the nearest inch, would come out to

$$28\; in^2$$

Thanks for the question dude. If you have any additional questions or don't understand how I did this, or even see a mistake of mine, feel free to let us know and me or another forum member would love to help!