what is the trajectory of the point?

x = 3cos(π/3)t - 1

y = 2 - 3cos(π/3)t

\(x = 3cos(π/3) t- 1\\ x = \frac{3t}{2} - 1\\ t=\frac{2(x+1)}{3} \\ y = 2 - 3cos(π/3)t\\ y = 2 - \frac{3t}{2}\\ t=\frac{-2(y-2)}{3}\\ \frac{2(x+1)}{3} =\frac{-2(y-2)}{3}\\ 1(x+1)=-(y-2) x+1=-y+2\\ x+y=1\)

\(y=1-x\)

Thanks  a lot

but is it circus or elipse or straight line or what?

y = 1 - x      .....definitely a straight line !!!!!!