+0  
 
0
400
3
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what is the units digit of the 99th number in the sequence: 1, 3, 9, 27, ...?

Guest Apr 5, 2017
 #1
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0

plz can some one tell  me the answersad

Guest Apr 5, 2017
 #2
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cryingcryingCphill plz can you tell me answer or Melodysadsad

Guest Apr 5, 2017
edited by Guest  Apr 5, 2017
 #3
avatar+87301 
+1

Note  that the series can be  written as

 

30, 31, 32, 33.......  =

 

34n, 34n + 1,  34n + 2,, 34n + 3........  for n = 0, 1, 2, 3 ..........

 

And the last digit has the repeating pattern

 

1, 3, 9, 7 ...........

 

So....the 99th term  is   398  =   34(24) + 2  which will end in 9

 

 

cool cool cool

CPhill  Apr 5, 2017

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