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what is the value of c that completes the square? z2(squared)+11/8z+c

 Apr 29, 2015

Best Answer 

 #1
avatar+130516 
+5

z^2 + (11/8)z + c

Take 1/2 of 11/8   =  11/16......now......square it  =    121 / 256......   this is "c"

So we have

z^2 + (11/7)z + 121 / 256 =  

(z + 11/16) ^2

 

  

 Apr 29, 2015
 #1
avatar+130516 
+5
Best Answer

z^2 + (11/8)z + c

Take 1/2 of 11/8   =  11/16......now......square it  =    121 / 256......   this is "c"

So we have

z^2 + (11/7)z + 121 / 256 =  

(z + 11/16) ^2

 

  

CPhill Apr 29, 2015

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