what is the value of c that completes the square? z2(squared)+11/8z+c

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Guest Apr 29, 2015

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Best Answer

z^2 + (11/8)z + c

Take 1/2 of 11/8 = 11/16......now......square it = 121 / 256...... this is "c"

So we have

z^2 + (11/7)z + 121 / 256 =

(z + 11/16) ^2

CPhill Apr 29, 2015

CPhill · Answer 1 · 2015-04-29T02:32:41

z^2 + (11/8)z + c

Take 1/2 of 11/8 = 11/16......now......square it = 121 / 256...... this is "c"

So we have

z^2 + (11/7)z + 121 / 256 =

(z + 11/16) ^2