What is the value of θ for the acute angle in a right triangle?
please help :c
Maybe I can put this picture to good use:
Now we can see that
θ + 58º = 90º
θ = 90º - 58º
θ = 32º
I don't really know what you mean by "for the acute angle in a right triangle," since both of the other angles in a right triangle are acute. But there are 2 angles that have the same sin as sin(32º) .
Those two angles are:
32º (acute) .....and..... 180º - 32º = 148º (obtuse)