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What is the value of the modulus of 6−4i ?

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 May 8, 2020
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The modulus of complex number  a + bi  is  sqrt( a2+ b2 )..

 

The modulus of  6 - 4i  is  sqrt( 62 + (-4)2 )  =  sqrt(  36 + 16 )  =  sqrt( 52 ).

 

I'll leave it to you to place it into reduced radical form ...

 May 8, 2020

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