What is the value of the sum 2^{-1} + 2^{-2} + 2^{-3} + ... + 2^{-9} + 2^{-10}? Give your answer as a simple fraction.
The sum, S, is given by
S = (1/2) [ 1 - r^n ] [ 1 - r ] where (1/2) is the first term [ 1/2 = 2^1 ] and r is the common ratio between terms = 1/2 and n is the number of terms = 10
So we have
S = (1/2) [ 1 - r^10 ] / [1/2] =
[ 1 - (1/2)^10 ] =
[ 2^10 - 1 ] / 2^10 =
1023 / 1024