What is the value of x in the equation 8x^2 - 6x + 1 = 0? I've been stuck on this for half an hour, the equation doesn't seem logical.
8x^2 - 6x + 1 = 0 factor, if we can
(4x - 1) (2x - 1) = 0 setting each factor to 0, we get x = 1/4 and x = 1/2
Darn, I knew I should have considered fractions. Thanks, CPhill.
OK......
+59 
