what is the value of x? (x-3)^2=x^2+(-3)^2
what is the value of b?
1 1
_____ = - ___
2b-2 4
x=0 and b=-1
(x-3)^2=x^2+(-3)^2 simplify and rearrange
x^2 - 6x + 9 - x^2 - 9 = 0
-6x = 0 divide both sides by -6
x = 0
1 / [2b - 2] = -1 / 4 cross-multiply
2 - 2b = 4 rearrange
-2 = 2b divide both sides by 2
b = -1