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what is the value of z in this equation. 8z^2=6z^2+38

 Dec 17, 2014

Best Answer 

 #1
avatar+26400 
+5

 8z^2=6z^2+38

$$\small{\text{
$
\begin{array}{rcl}
8z^2 &=& 6z^2+38 \quad | \quad -6z^2 \\
8z^2-6z^2 &=& 38 \\
(8-6)z^2 &=& 38 \\
2z^2 &=& 38 \quad | \quad :2 \\\\
z^2 &=& \dfrac{38}{2} \\\\
z^2 &=& 19\quad | \quad \pm\sqrt \\
z_{1,2} &=& \pm\sqrt{19} \\
\end{array}
$
}} $\\\\$
\small{\text{
$
z_1 &=& 4.35889894354 $ and $ z_2 &=& -4.35889894354
$
}}$$

 Dec 17, 2014
 #1
avatar+26400 
+5
Best Answer

 8z^2=6z^2+38

$$\small{\text{
$
\begin{array}{rcl}
8z^2 &=& 6z^2+38 \quad | \quad -6z^2 \\
8z^2-6z^2 &=& 38 \\
(8-6)z^2 &=& 38 \\
2z^2 &=& 38 \quad | \quad :2 \\\\
z^2 &=& \dfrac{38}{2} \\\\
z^2 &=& 19\quad | \quad \pm\sqrt \\
z_{1,2} &=& \pm\sqrt{19} \\
\end{array}
$
}} $\\\\$
\small{\text{
$
z_1 &=& 4.35889894354 $ and $ z_2 &=& -4.35889894354
$
}}$$

heureka Dec 17, 2014

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