What is the vertex of the graph of the quadratic function f(x)=x2+6x+10

 f(x)=x²+6x+10

This is a quadratic function in the "y= ax² + bx + c" form, so to find the x-coordinate of the vertex you would find (-b/2a)

For this problem it would be: (-6/2)

= -3

Now plug in -3 as x in the equation:

y = (-3)² + 6 * -3 + 10

y = 9 + (-18) + 10

y = 1

So the vertex would be (-3, 1)