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What is the x-coordinate of the point on the x-axis that is equidistant from points  (-2, 0) and (0, 4)?

 Jan 20, 2021
 #1
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Call the point we are looking for  (a, 0)

 

Since we are equating distances,  we can equate  the distances^2

 

So

 

( a - -2)^2  +(0 - 0)^2  = ( a - 0)^2  + (4 - 0)^2     simplify

 

(a + 2)^2   =  a^2  +  16

 

a^2 + 4a + 4  = a^2 + 16

 

4a + 4 =  16

 

4a  = 12

 

a =   3 =   the x coordinate we are  looking for

 

 

cool cool cool

 Jan 20, 2021

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