First we're going to want to factor these out.
f(x)=x^3+x^2-42x
f(x) = (x)(x^2+x-42) ---this second part can be factored
f(x) = (x)(x+6)(x-7)
Now that this is factored completely, we can find the zeros. The "zeros" of a polynomial funtion like we have here are the numbers you could put in for x to make f(x) = 0.
For instance, if we put in -6 for x, we would get this:
f(x)=(-6)(-6+6)(-6-7)
f(x)=(-6)(0)(-13) ---anything and everything multiplied by zero is zero.
f(x) = 0
Basically you find the opposites of the numbers next to x.
So the zeros are 0, -6, and 7.
First we're going to want to factor these out.
f(x)=x^3+x^2-42x
f(x) = (x)(x^2+x-42) ---this second part can be factored
f(x) = (x)(x+6)(x-7)
Now that this is factored completely, we can find the zeros. The "zeros" of a polynomial funtion like we have here are the numbers you could put in for x to make f(x) = 0.
For instance, if we put in -6 for x, we would get this:
f(x)=(-6)(-6+6)(-6-7)
f(x)=(-6)(0)(-13) ---anything and everything multiplied by zero is zero.
f(x) = 0
Basically you find the opposites of the numbers next to x.
So the zeros are 0, -6, and 7.