what is two plus five

Let's make it more complicated.

The lowest x value where f(x) = 1 is your answer. 

 

f(x) = (((-((x)(x-(((7*(10^0)-2+5)*7)/10+2-5+3)-1)(x-(((7*(10^0)-2+5)*7)/10+2-5+3)))/((((x)(x-(((7*(10^0)-2+5)*7)/10+2-5+3)-1)(x-(((7*(10^0)-2+5)*7)/10+2-5+3))))^2)^0.5))+1)/2

 

Or maybe it isn't

sqrt((-7)^2)*

Can't do the square root of a negative number pal