Take logs of both sides
log(5x) = log(17)
Use the property of logarithms that states log(ab) = b*log(a)
x*log(5) = log(17)
x = log(17)/log(5)
$${\mathtt{x}} = {\frac{{log}_{10}\left({\mathtt{17}}\right)}{{log}_{10}\left({\mathtt{5}}\right)}} \Rightarrow {\mathtt{x}} = {\mathtt{1.760\: \!374\: \!427\: \!722\: \!587\: \!7}}$$
.
Take logs of both sides
log(5x) = log(17)
Use the property of logarithms that states log(ab) = b*log(a)
x*log(5) = log(17)
x = log(17)/log(5)
$${\mathtt{x}} = {\frac{{log}_{10}\left({\mathtt{17}}\right)}{{log}_{10}\left({\mathtt{5}}\right)}} \Rightarrow {\mathtt{x}} = {\mathtt{1.760\: \!374\: \!427\: \!722\: \!587\: \!7}}$$
.