2x2 = x2 - 1
First, subtract x2 from both sides.
x2= -1
Then take the square root of both sides.
so $${\mathtt{x}} = {\sqrt{-{\mathtt{1}}}}$$ and $${\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{-{\mathtt{1}}}}$$
But in real numbers, you cannot have the square root of a negative number. So instead, there is this number, $${i}$$ , the imaginary number.
$${i}$$ by definition is the square root of -1
So x = i or x = -i
2x2 = x2 - 1
First, subtract x2 from both sides.
x2= -1
Then take the square root of both sides.
so $${\mathtt{x}} = {\sqrt{-{\mathtt{1}}}}$$ and $${\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{-{\mathtt{1}}}}$$
But in real numbers, you cannot have the square root of a negative number. So instead, there is this number, $${i}$$ , the imaginary number.
$${i}$$ by definition is the square root of -1
So x = i or x = -i