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what is x if x+x-1+x*2-5=169

 Mar 11, 2015

Best Answer 

 #1
avatar+130516 
+5

 x+x-1+x*2-5=169     simplify

2x - 1 + x^2 - 5  = 169

x^2 + 2x - 6  = 169      subtract 169 from both sides

x^2 + 2x - 175  = 0      this will not factor......using the on-site solver, we have

 

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{175}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{11}}}}{\mathtt{\,-\,}}{\mathtt{1}}\\
{\mathtt{x}} = {\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{11}}}}{\mathtt{\,-\,}}{\mathtt{1}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{14.266\: \!499\: \!161\: \!421\: \!599\: \!4}}\\
{\mathtt{x}} = {\mathtt{12.266\: \!499\: \!161\: \!421\: \!599\: \!4}}\\
\end{array} \right\}$$

And those are the two solutions.....

 

  

 Mar 12, 2015
 #1
avatar+130516 
+5
Best Answer

 x+x-1+x*2-5=169     simplify

2x - 1 + x^2 - 5  = 169

x^2 + 2x - 6  = 169      subtract 169 from both sides

x^2 + 2x - 175  = 0      this will not factor......using the on-site solver, we have

 

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{175}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{11}}}}{\mathtt{\,-\,}}{\mathtt{1}}\\
{\mathtt{x}} = {\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{11}}}}{\mathtt{\,-\,}}{\mathtt{1}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{14.266\: \!499\: \!161\: \!421\: \!599\: \!4}}\\
{\mathtt{x}} = {\mathtt{12.266\: \!499\: \!161\: \!421\: \!599\: \!4}}\\
\end{array} \right\}$$

And those are the two solutions.....

 

  

CPhill Mar 12, 2015

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