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what is x if y = 4000       1600x^3+1200x^2+800x = 4000

 Dec 14, 2014

Best Answer 

 #1
avatar+118723 
+5

Your question doesn't make sense but I think that you are asking for this to be solved.

$$\\1600x^3+1200x^2+800x = 4000\\
4x^3+3x^2+2x = 10\\
4x^3+3x^2+2x-10 = 0\\$$

 

The only real answer (from the graph) is

approx = 1.05

https://www.desmos.com/calculator/vhgrr2n6h6

 Dec 15, 2014
 #1
avatar+118723 
+5
Best Answer

Your question doesn't make sense but I think that you are asking for this to be solved.

$$\\1600x^3+1200x^2+800x = 4000\\
4x^3+3x^2+2x = 10\\
4x^3+3x^2+2x-10 = 0\\$$

 

The only real answer (from the graph) is

approx = 1.05

https://www.desmos.com/calculator/vhgrr2n6h6

Melody Dec 15, 2014

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