\(\frac{4^x}{3}=\frac{1}{12}\) Multiply both sides by 3
\(4^x=\frac{1}{4}\) Take log using the law: \(a^b=c\) = \(log_ac=b\)
\(log_4\frac{1}{4}=x\) Evaluate by indices laws or by calculator. Indeed we know that 4^-1=1/4 so,
\(log_4\frac{1}{4}\)= -1
Therefore,
x= -1
