+0  
 
0
844
7
avatar+870 

What is:

$$\sqrt{\sqrt[{\sqrt[-1]{2}^\sqrt{9}}]{6}}$$

 Apr 29, 2015

Best Answer 

 #2
avatar+118677 
+5

$$\\\sqrt{\sqrt[{\sqrt[-1]{2}^\sqrt{9}}]{6}}\\\\$$

 

I do not think that this has any definative meaning  

 Apr 30, 2015
 #1
avatar+961 
+3

i think it a image number not sure 

 Apr 29, 2015
 #2
avatar+118677 
+5
Best Answer

$$\\\sqrt{\sqrt[{\sqrt[-1]{2}^\sqrt{9}}]{6}}\\\\$$

 

I do not think that this has any definative meaning  

Melody Apr 30, 2015
 #3
avatar+870 
0

The answer is 1296

 Apr 30, 2015
 #4
avatar+118677 
0

You need to show your working Einstein :/

 

$$\sqrt[-1]{2}$$    I can guess at what it might mean but I have never seen an expression like this before !

 Apr 30, 2015
 #5
avatar+870 
0

You can verify by yourself, sqrt(sqrt(6,sqrt(2,-1)^sqrt(9)))=1296

 Apr 30, 2015
 #6
avatar+118677 
0

I want you to verify it by hand. :)

 Apr 30, 2015
 #7
avatar+870 
0

$$\sqrt{\sqrt[{\sqrt[-1]{2}^\sqrt{9}}]{6}}\\
=\sqrt{\sqrt[{\sqrt[-1]{2}^3}]{6}}\\
=\sqrt{\sqrt[\left ( \frac{1}{2} \right )^3]{6}}\\
=\sqrt{\sqrt[\frac{1}{8}]{6}}\\
=\sqrt{1679616}
=1296$$

.
 Apr 30, 2015

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