+18 Howdy, I'm currently studying for finals and reviewing the 10 chapters of the work we've learned, I've reviewed about 7 but am currently stuck on this type of problem, I cannot find my notes and I dont know what kind of problems these are, please help!(It may be something I actually know but don't know how to solve in text form)
A rectangle has side lengths of 5 feet and 12 feet. What is the length of the diagonals of the rectangle?
Thank you for going over this problem and helping me with it, I may ask more questions as the afternoon ends here in the U.S
+5478 Hello Itoen,
You can use the Pythagorean Theorem $${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$ to solve for the diagonal of a rectangle:)
A diagonal divides the rectangle into 2 congruent right triangles.
The sides 5 and 12 would be a and b, and c would be the longer side (the diagonal)
So $${{\mathtt{5}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{12}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$
Simplify.
169 = c2
c = 13
+5478 Hello Itoen,
You can use the Pythagorean Theorem $${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$ to solve for the diagonal of a rectangle:)
A diagonal divides the rectangle into 2 congruent right triangles.
The sides 5 and 12 would be a and b, and c would be the longer side (the diagonal)
So $${{\mathtt{5}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{12}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$
Simplify.
169 = c2
c = 13
