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What's the answer to (-4 (+/-) √4 - 4(32)(5)) / (2(32))

Guest Aug 27, 2017
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\(\frac{-4\,\pm\,\sqrt{4-4(32)(5)}}{2(32)} \\~\\ =\,\frac{-4\,\pm\,\sqrt{4-640}}{64} \\~\\ =\,\frac{-4\,\pm\,\sqrt{-636}}{64} \\~\\ =\,\frac{-4\,\pm\,\sqrt{-1\cdot2\cdot2\cdot3\cdot53}}{64} \\~\\ =\, \frac{-4\,\pm\,\sqrt{-1}\,\cdot\,\sqrt{2\cdot2}\,\cdot\,\sqrt{3\cdot53}}{64} \\~\\ =\, \frac{-4\,\pm \,i\,\cdot\,2\,\cdot\,\sqrt{159}}{64} \\~\\ =\, \frac{-4\,\pm\,2i\sqrt{159}}{64}\)

 

If this is from a quadratic equation, is it    \(\frac{-4\pm\sqrt{4^2-4(32)(5)}}{2(32)} \)    ?

hectictar  Aug 27, 2017
edited by hectictar  Aug 27, 2017

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