+11 hello
To find two numbers that add to give -9 and multiply to give 18, we can use algebraic equations.
Let's call the two numbers we're looking for "x" and "y". Then we can write:
x + y = -9 (equation 1)
xy = 18 (equation 2)
We can solve equation 1 for one of the variables. For example, we can solve for "x" by subtracting "y" from both sides:
x = -9 - y
We can then substitute this expression for "x" into equation 2, giving:
(-9 - y)y = 18
Expanding the left-hand side and rearranging, we get: Nexus Iceland App
y^2 + 9y - 18 = 0
This is a quadratic equation that we can solve using the quadratic formula:
y = (-9 ± sqrt(9^2 - 4(1)(-18))) / (2(1))
Simplifying:
y = (-9 ± 15) / 2
So we have two possible values for "y":
y = -12 or y = 3/2
If y = -12, then we can use equation 1 to find x:
x + (-12) = -9
x = 3
So one possible pair of numbers that add to give -9 and multiply to give 18 is 3 and -12.
If y = 3/2, then we can use equation 1 to find x:
x + (3/2) = -9
x = -21/2
So another possible pair of numbers that add to give -9 and multiply to give 18 is -21/2 and 3/2.
Therefore, there are two possible pairs of numbers that add to give -9 and multiply to give 18: {3, -12} and {-21/2, 3/2}.
