+0  
 
0
661
1
avatar

$${\frac{\left({\mathtt{4}}{\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\left({\mathtt{3}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{12}}\right)}}$$

 Jul 10, 2014

Best Answer 

 #1
avatar+130518 
+5

The only thing we would need to check here is if anything made the denominator = 0.

However, a quick look tells us that this can't happen because 3x^2 is always positive (or, 0) and when I add 12 to a positive - or 0- I still have a positive number. Hence, no "x" valuies make the denominator = 0.

 

  

 Jul 10, 2014
 #1
avatar+130518 
+5
Best Answer

The only thing we would need to check here is if anything made the denominator = 0.

However, a quick look tells us that this can't happen because 3x^2 is always positive (or, 0) and when I add 12 to a positive - or 0- I still have a positive number. Hence, no "x" valuies make the denominator = 0.

 

  

CPhill Jul 10, 2014

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