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what valur of u makes this equation true: u-9=7u+7

 Feb 23, 2015

Best Answer 

 #2
avatar+23254 
+5

u - 9  =  7u + 7

Subtract u from both sides:

    -9  =  6u + 7

Subtract 7 from both sides:

   -16  =  6u

Divide both sides by 6:

   -16/6  =  u

--->  u  =  -8/3

 Feb 23, 2015
 #1
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0

It's theoretically simply a matter of solving the equation, but not really in this case:

u - 9 = u + 7

First get all constants (regular numbers) on one side and all variables on the other:

u = u + 7 + 9 (add 9 to both sides)

u = u + 16 (simplify)

      ^ To get rid of this 'u', we must subtract 'u' from both sides:

u - u = 16 (subtract u from both sides)

0 = 16 (simplify -- any number minus itself is zero)

0 never equals 16!

Therefore, there is no value that could possibly be substituted in for u that would make the statement true.

Don't believe me? Try it:

What if u = 2?

2 - 9 = 2 + 7

-7 = 9

-7 NEVER equals 9!

 

Here's a shorter way to do it:

Take the original equation

u - 9 = u + 7

and subtract u from both sides.

-9 = 7

-9 NEVER equals 7!

 Feb 23, 2015
 #2
avatar+23254 
+5
Best Answer

u - 9  =  7u + 7

Subtract u from both sides:

    -9  =  6u + 7

Subtract 7 from both sides:

   -16  =  6u

Divide both sides by 6:

   -16/6  =  u

--->  u  =  -8/3

geno3141 Feb 23, 2015

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