What would be measurement of BPD?

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What would be m<BPD?

AnthonyRussel Feb 27, 2016

edited by AnthonyRussel Feb 27, 2016
edited by AnthonyRussel Feb 27, 2016

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Best Answer

+129845

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Connect BC

Then m< CBA = (1/2) minor arc AC = (1/2)(164) = 82 = m<CBP

And m< DCB = (1/2) minor arc BD = (1/2)(146) = 73 = m< PCB

Then PCB forms a triangle

And, by the Exterior Angle Theorem, m<BPD = m< CBP + m<PCB = 82 + 73 = 155

CPhill Feb 27, 2016

1⁺⁰ Answers

+129845

+5

Best Answer

Connect BC

Then m< CBA = (1/2) minor arc AC = (1/2)(164) = 82 = m<CBP

And m< DCB = (1/2) minor arc BD = (1/2)(146) = 73 = m< PCB

Then PCB forms a triangle

And, by the Exterior Angle Theorem, m<BPD = m< CBP + m<PCB = 82 + 73 = 155

CPhill Feb 27, 2016

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