+14915 whats 2 over 3 divided by negetive 3 over 4
\(\frac{2}{3}:\frac{-3}{4}=-\frac{2}{3}\times\frac{4}{3}\color{blue}=-\frac{8}{9}\)
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+2441 I believe you want to evaluate the expression \(\frac{\frac{\frac{2}{3}}{-3}}{4}\).
When expressions are difficult to evaluate, I like to set the value to a number (I will use x)
| \(x=\frac{\left(\frac{\left(\frac{2}{3}\right)}{-3}\right)}{4}\) | Multiply by 4 on both sides of the equation. |
| \(4x=\frac{\left(\frac{2}{3}\right)}{-3}\) | Multiply by -3 on both sides on both sides. |
| \(-12x=\frac{2}{3}\) | Multiply by 3 on both sides. |
| \(-36x=2\) | Divide by -36 on both sides to isolate x |
| \(x=-\frac{2}{36}=-\frac{1}{18}=-0.0\overline{55}\) | |
I like doing this because it can sometimes make a seemingly hard problem easier. However, you do not have to do this. You can use your knowledge of fractions and its respective rules to solve this expression, too.
| \(\frac{\left(\frac{\left(\frac{2}{3}\right)}{-3}\right)}{4}\) | First, let's simply just worry about (2/3)/(-3) |
| \(\frac{\frac{2}{3}}{-3}\) | Use the fraction rule that \(\frac{\frac{a}{b}}{c}=\frac{a}{b*c}\) |
| \(\frac{2}{3*-3}=\frac{2}{-9}\) | Now, insert this into the equation for (2/3)/(-3) |
| \(\frac{\frac{2}{-9}}{4}\) | Let's apply the same fraction rule as before. |
| \(\frac{\frac{2}{-9}}{4}=\frac{2}{-9*4}=\frac{2}{-36}\) | Simplify the fraction by noting that both the numerator and denominator are even, so the GCF is, at least, 2. |
| \(-\frac{2}{36}=-\frac{1}{18}=-0.0\overline{55}\) | |
