whats the procedior of "(1-sqrt(10))^2" ?

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whats the procedior of "(1-sqrt(10))^2" ?

Guest Jun 4, 2014

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+130511

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(1 - √10 )² =

(1 - √10 ) (1 - √10 ) =

1 -1√10 - 1√10 + √10 * √10 =

1 - 2√10 + 10 =

11 - 2√10

CPhill Jun 4, 2014

1⁺⁰ Answers

+130511

+5

Best Answer

(1 - √10 )² =

(1 - √10 ) (1 - √10 ) =

1 -1√10 - 1√10 + √10 * √10 =

1 - 2√10 + 10 =

11 - 2√10

CPhill Jun 4, 2014

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