2 trains whose rates differ by 8mph leave stations that are 432 miles apart at 10 am. If the trains meet at 2pm, what is the rate of each train?

NoobGuest Jun 19, 2019

#1**+2 **

Faster train = x+8

Slower train = x

The trains approach each other at their combined speed x + x+8

and at this speed they cover the 432 miles in 4 hours (from 10 AM to 2 PM)

Rate * Time = distance

(x+ x+8) * 4 = 432

4x+4x+32 = 432

8x = 400

x = 50 mph = slower train

x+8 = 58 mph = faster train

ElectricPavlov Jun 19, 2019

#1**+2 **

Best Answer

Faster train = x+8

Slower train = x

The trains approach each other at their combined speed x + x+8

and at this speed they cover the 432 miles in 4 hours (from 10 AM to 2 PM)

Rate * Time = distance

(x+ x+8) * 4 = 432

4x+4x+32 = 432

8x = 400

x = 50 mph = slower train

x+8 = 58 mph = faster train

ElectricPavlov Jun 19, 2019