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When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm?

Please show all the steps.

Guest Mar 11, 2017

Best Answer 

 #1
avatar+7348 
+5

When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm? {nl} Please show all the steps.

 

\(15N\times x=60N\times(100cm-x)\)

 

\(15N\times x = 6000Ncm - 60N\times x\)

 

\(x=\frac{6000Ncm}{75N}\)

 

\(x=80cm\)

 

\( The\ length \ of \ the\ input\ arm \ is \ 80cm.\)

 

laugh  !

asinus  Mar 12, 2017
edited by asinus  Mar 12, 2017
 #1
avatar+7348 
+5
Best Answer

When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm? {nl} Please show all the steps.

 

\(15N\times x=60N\times(100cm-x)\)

 

\(15N\times x = 6000Ncm - 60N\times x\)

 

\(x=\frac{6000Ncm}{75N}\)

 

\(x=80cm\)

 

\( The\ length \ of \ the\ input\ arm \ is \ 80cm.\)

 

laugh  !

asinus  Mar 12, 2017
edited by asinus  Mar 12, 2017

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