When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm?

Please show all the steps.

Guest Mar 11, 2017

#1**+5 **

When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm? {nl} Please show all the steps.

\(15N\times x=60N\times(100cm-x)\)

\(15N\times x = 6000Ncm - 60N\times x\)

\(x=\frac{6000Ncm}{75N}\)

\(x=80cm\)

\( The\ length \ of \ the\ input\ arm \ is \ 80cm.\)

!

asinus
Mar 12, 2017

#1**+5 **

Best Answer

When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm? {nl} Please show all the steps.

\(15N\times x=60N\times(100cm-x)\)

\(15N\times x = 6000Ncm - 60N\times x\)

\(x=\frac{6000Ncm}{75N}\)

\(x=80cm\)

\( The\ length \ of \ the\ input\ arm \ is \ 80cm.\)

!

asinus
Mar 12, 2017