When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm?
Please show all the steps.
When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm? {nl} Please show all the steps.
\(15N\times x=60N\times(100cm-x)\)
\(15N\times x = 6000Ncm - 60N\times x\)
\(x=\frac{6000Ncm}{75N}\)
\(x=80cm\)
\( The\ length \ of \ the\ input\ arm \ is \ 80cm.\)
!
When a 15 newton force is applied to on end of a lever 100 cm long, a 60 newton weight is attached to the opposit end is lifted. What is the length of the input arm? {nl} Please show all the steps.
\(15N\times x=60N\times(100cm-x)\)
\(15N\times x = 6000Ncm - 60N\times x\)
\(x=\frac{6000Ncm}{75N}\)
\(x=80cm\)
\( The\ length \ of \ the\ input\ arm \ is \ 80cm.\)
!