when does the diver hit the water

Question

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3

Guest Sep 30, 2015

+130518

+5

Best Answer

h(t)=-5t^2+7t+6

Assuming the water height = 0, we have

0 = -5t^2 + 7t + 6 factor this

0 = (-5t -3)(t - 2) setting each factor to 0, we have that t = -3/5s [reject this answer] and t = 2 seconds [this is the correct answer]

The diver hits the water after 2 seconds

CPhill Sep 30, 2015

CPhill · Answer 1 · 2015-09-30T11:32:41

h(t)=-5t^2+7t+6

Assuming the water height = 0, we have

0 = -5t^2 + 7t + 6 factor this

0 = (-5t -3)(t - 2) setting each factor to 0, we have that t = -3/5s [reject this answer] and t = 2 seconds [this is the correct answer]

The diver hits the water after 2 seconds