When Joe dives off a diving board, the equation of his pathway can be modeled by h=-16t^2+15t+12. Find the time it will take to reach the wa

 

(15- \sqrt(993))/(32) is your awnser after using the quadratic formula which is x = -b +- sqrt(b^2-4ac)/32 

H = 0 when he smacks the water in a big ol' belly flop:

 

0=-16t^2+15t+12           

       a = -16    b = 15     c = 12   for the Quadratic Formula

 

\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

 

\(t = {-15 \pm \sqrt{15^2-4(-16)(12)} \over 2(-16)}\)

 

 if you do the calculation,      t =    15/32   +  \(\sqrt{993}\) /32      = 1.4535 seconds