Which answer describes the function f(x)=2x 3 −x 2 ?

If it's even....then

f(-x)  =  f(x)

So  f(-x)  =  2(-x)^3 - (-x)^2    =  -2x^3 - x^2   but this does not =  f(x)

If it's odd....then  f(-x)  = - f(x)

And  - f(x)     =     -[2x^3  - x^2]  =  -2x^3 + x^2    but  this doesn't = f(-x)  

So.....neither 

The function doesn't  "rise" or "fall"  from (2, 6 )  ....so it's constant here