First one - this is odd because if ( -x, y) is on the graph, then so is (x , -y)
Second one....
If even then m(x) = m(-x)
If odd then m(-x) = - m(x)
So
g(x) = x^4 - x^2 = (-x)^4 - (-x)^2 = x^4 - x^2 so....even
f(x) = x^3 - 3x^2 = (-x)^3 - 3(-x)^2 = -x^3 - 3x^2 not even
f(x) = x^3 - x^2 -f(x) = - [ x^3 - 3x^2 ]= -x^2 + 3x^2 not odd, either
So....neither
h(x) = x^3 - x
h(-x)= (-x)^3 - (-x) = -x^3 + x not even
-h(x) = -[ x^2 -x ] = -x^3 + x not odd , either
So...neither